What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
int main() {
int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"};
map
for (int i = 0; i < 10; i++) {
m.push_back(pair
}
for (map
cout << i?>first << " ";
}
return 0;
}
What will happen when you attempt to compile and run the code below, assuming that file test.in contains the following sequence: 1 2 3?
#include
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { ifstream f("test.in"); list for( ; f.good() ; ) { int i; f>>i; l.push_back(i); } f.close(); for_each(l.begin(), l.end(), Out return 0; } Program will output:
Which sentence is correct about the code below?
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; }
void setA(int a) { this?>a = a; }
/* Insert Code Here */
};
struct add10 { void operator()(A & a) { a.setA(a.getA() + 10); } };
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector v1(t, t + 10);
for_each(v1.begin(), v1.end(), add10());
vector::iterator it = find(v1.begin(), v1.end(), A(7));
cout << it?>getA() << endl;
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
while (start != end) {
std::cout << *start << " "; start++;
}
}
class A {
int a;
public:
A(int a):a(a){}
operator int () const { return a;}int getA() const { return a;}
};
struct R {
int val;
R(int v):val(v){}
bool operator ()(const A & a) { return a>val;} };
int main() {
int t1[] ={ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
list l1(t1, t1 + 10);
R r(4);l1.remove_if(r);
print(l1.begin(), l1.end()); cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={5,6,8,2,1}; vector sort(t1, t1+5); sort(t2, t2+5); set_union(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What will happen when you attempt to compile and run the code below, assuming that file test.in contains the following sequence: 1 2 3?
#include
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { ifstream f("test.in"); list for( ; !f.fail() ; ) { int i; f>>i; l.push_back(i); } f.close(); for_each(l.begin(), l.end(), Out return 0; } Programwill output:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
set
vector
swap_ranges(s1.begin(), s1.end(), v1.begin());
for_each(v1.begin(), v1.end(), myfunction);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
map
for(vector
stringstream s; s<<*i<<*i; m.insert(pair
}
for(map
cout<<*i<<" ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; } void setA(int a) { this?>a = a; }
};
int main () {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
deque
int number = count(d.begin(), d.end(), 2);
cout<< number< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
deque
set
for_each(v1.begin(), v1.end(), myfunction); // Line I
for_each(d1.begin(), d1.end(), myfunction); // Line II
for_each(s1.begin(), s1.end(), myfunction); // Line III
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={6,10,8,7,9}; vector transform(t1,t1+5,t2,v1.rbegin(), plus for_each(v1.rbegin(), v1.rend(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
using namespace std;
template
class A {
T_v;
public:
A() {}
A(T v): _v(v){}
T getV() { return _v; }
void add(T a) { _v+=a; }
template
U get(U a) {
return (U)(_v);
}
};
int main()
{
A
a.add(10);
cout.setf( ios::showpoint);
cout << a.getV() << " " << a.get(1.0)< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; } void setA(int a) { this?>a = a; }
bool operator==(A & b) { return a == b.a; }
};
struct Compare{
bool operator()(const A & a, const A & b) {return a.getA()==b.getA();};
};
int main () {
int t[] = {1,2,3,4,5,1,2,3,4,5};
vector v (t,t+10);
vector::iterator it;
A m1[] = {A(1), A(2), A(3)};
it = search (v.begin(), v.end(), m1, m1+3, Compare());
cout << "First found at position: " << it?v.begin() << endl;
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void print(int v) { cout< struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++; } }; bool predicate(int v) { return v%2==0; } int main() { vector generate_n(v1.begin(), 10, Sequence(1)); set remove_if(s1.begin(), s1.end(), predicate); for_each(s1.begin(), s1.end(), print);cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { B t1[]={3,2,4,1,5}; B t2[]={5,6,8,2,1}; vector v1(10,0); sort(t1, t1+5); sort(t2, t2+5); set_symmetric_difference(t2,t2+5,t1,t1+5,v1.begin()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
struct display {
void operator() (int i) {cout << " " << i;}
};
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
deque
set
for_each(v1.begin(), v1.end(), display); //Line I
for_each(d1.begin(), d1.end(), *(new display())); // Line II
for_each(s1.begin(), s1.end(), display()); // Line III
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={5,6,8,2,1}; vector sort(t1, t1+5); sort(t2, t2+5); set_difference(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
using namespace std;
int main()
{
cout.setf(ios::hex, ios::basefield);
cout<<100<<" ";
cout.unsetf(ios::hex);
cout<<100<<" ";
return 0;
}
Program outputs:
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
set
multiset
s1.insert(s.begin(),s.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
for(multiset
cout<<*i<<" ";
}
return 0;
}
The output will be:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
void print(T start, T end) {
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main()
{
int t1[] ={ 1, 7, 8, 4, 5 };
list
int t2[] ={ 3, 2, 6, 9, 0 };
deque
l1.sort();
d1.sort();
l1.merge(d1);
print(l1.begin(), l1.end());
print(d1.begin(), d2.end()); cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;} };
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { B t1[]={3,2,4,1,5}; B t2[]={6,10,8,7,9}; vector v1(5); transform(t1,t1+5,t2,v1.rbegin(), plus()); for_each(v1.rbegin(), v1.rend(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
bool mycomparison (int first, int second){return first>second;}
template
void print(T start, T end) {
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main()
{
int t1[] ={ 1, 7, 8, 4, 5 };
list
int t2[] ={ 3, 2, 6, 9, 0 };
list
l1.sort(mycomparison);
l2.sort(mycomparison);
l1.merge(l2,mycomparison);
print(l1.begin(), l1.end());
print(l2.begin(), l2.end()); cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; set s1(t, t+10); sort(s1.begin(), s1.end()); for_each(s1.begin(), s1.end(), Out(cout));cout< return 0; } Program outputs:
What will be output of the program when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
int main(){
int second[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
string first[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight","zero"};
multimap
for(int i=0; i<10; i++) {
m.insert(pair
}
m[0]="ten";
m.insert(pair
for(multimap
cout<second<<" ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
bool compare(int a, int b) { return a == b; }
int main () {
int t[] = {1,2,3,4,5,1,2,3,4,5};
vector
vector
int m1[] = {1, 2, 3};
while ( (it = find_first_of (it, v.end(), m1, m1+3)) != v.end()) {
cout< } cout<< endl; return 0; }
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main(){
vector
set
for(int i=10; i>0; i??) {
v.push_back(i);
s.push_back(i);
}
print(v.begin(), v.end()); print(s.begin(), s.end());cout< return 0; } The output will be:
Which changes introduced independently will allow code to compile and display 0 1 8 9 (choose all that apply)
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2 */
int main(){
A t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vectorv(t, t+10);
s1.insert(v.begin(),v.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
for(set::iterator i=s1.begin();i!= s1.end(); i++) {
cout<getA()<<" ";
}
cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int second[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 10 };
string first[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight"," ten"};
map
for(int i=0; i<10; i++) {
m.insert(pair
}
if (m[11] == "eleven") {
cout<<"eleven ";
}
for(map
cout<second<<" ";
}
cout< return 0; }
Which keywords can be used to define template type parameters? Choose all possible answers:
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
set
s1.insert(v.begin(),v.end());
pair
range = s1.equal_range(6);
cout<<*range.first<<" "<<*range.second< return 0; } The output will be:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
set
set
for(set
cout<<*i<<" ";
}
for(set
cout<<*i<<" ";
}
cout< return 0; }
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
multiset
multiset
for(multiset
cout<<*i<<" ";
}
for(multiset
cout<<*i<<" ";
}
cout< return 0; } The output will be:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque sort(d1.begin(), d1.end()); deque for_each(it, d1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
template
class A {
T_v;
public:
A() {}
A(T v): _v(v){}
T getV() { return _v; }
void add(T & a);
void add(string & a);
};
template
void A
void A
_v.insert(0, a);
}
int main()
{
A
string s(" world!");
a.add(s);
cout << a.getV() < return 0; }